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.2x^2+3x-69=0
a = .2; b = 3; c = -69;
Δ = b2-4ac
Δ = 32-4·.2·(-69)
Δ = 64.2
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-\sqrt{64.2}}{2*.2}=\frac{-3-\sqrt{64.2}}{0.4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+\sqrt{64.2}}{2*.2}=\frac{-3+\sqrt{64.2}}{0.4} $
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